Shouldn’t that be the limit as x approaches 4? since that’s where the asymptote occurs…
mathfail
Only when you are trying to find asymptotes… The way it’s written right now the limit is 0.
MetaSynapse
Yeah I realised that after posting :S
But it’s not really a limit, is it. Or am I miising something…
somerandomguy
You’re missing something. It goes to 0. The question is: what does that equation do as x approaches 5? As x approaches 5, the numerator is 2-2=0 and the denominator is 5-4=1. 0/1=0.
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It’s 0!!!
Shouldn’t that be the limit as x approaches 4? since that’s where the asymptote occurs…
Only when you are trying to find asymptotes… The way it’s written right now the limit is 0.
Yeah I realised that after posting :S
But it’s not really a limit, is it. Or am I miising something…
You’re missing something. It goes to 0. The question is: what does that equation do as x approaches 5? As x approaches 5, the numerator is 2-2=0 and the denominator is 5-4=1. 0/1=0.