Shouldn’t that be the limit as x approaches 4? since that’s where the asymptote occurs…

mathfail

Only when you are trying to find asymptotes… The way it’s written right now the limit is 0.

MetaSynapse

Yeah I realised that after posting :S
But it’s not really a limit, is it. Or am I miising something…

somerandomguy

You’re missing something. It goes to 0. The question is: what does that equation do as x approaches 5? As x approaches 5, the numerator is 2-2=0 and the denominator is 5-4=1. 0/1=0.

DudeIt’s 0!!!

MetaSynapseShouldn’t that be the limit as x approaches 4? since that’s where the asymptote occurs…

mathfailOnly when you are trying to find asymptotes… The way it’s written right now the limit is 0.

MetaSynapseYeah I realised that after posting :S

But it’s not really a limit, is it. Or am I miising something…

somerandomguyYou’re missing something. It goes to 0. The question is: what does that equation do as x approaches 5? As x approaches 5, the numerator is 2-2=0 and the denominator is 5-4=1. 0/1=0.